Question

if the angle of the top of a tower of height 100mt from a point to its foot is tan^-1(4\5),then distance from the point its foot is​

Answer 1

Answer:

Step-by-step explanation:

Let distance from point to foot of tower is x

given, height of tower = 100m

given, α = tan^-1(4/5)

now, using tanα = Perpendicular/base

or, tan{tan^-1(4/5)} = 100/x

or, 4/5 = 100/x

or, x = 100 × 5/4 = 125m

therefore, distance from point to the foot of the tower is 125m.