If the angle P,Q,R and S taken in order, are in the ratio 8:2:7:3, then find the difference between the measure of angle P and angle S.
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Answered by
2
P=3x, Q=7x, R=6x, S=4x
P+Q+R+S=360
3x+7x+6x+4x=360
20x=360
x=18
p=3x=54
Q=7x=126
R=6x=108
S=4x=72
P+Q+R+S=360
3x+7x+6x+4x=360
20x=360
x=18
p=3x=54
Q=7x=126
R=6x=108
S=4x=72
Nirbhay22:
Thanks for helping but it's not 6x it's 2x
Answered by
1
Answer:
Let the angle be x
Step-by-step explanation:
thus, 8x+2x+7x+3x= 360 [angle sum property of a quadrilateral]
20x= 360
x=18
Hence, 8x=18*8 =144
2x=18*2 =36
7x= 18*7 =126
3x= 18*3 =54
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