Question

if the angles (2x-10)° and (x-5)° are complementary angles then 'x' is...​

Answer 1

Given :

• Angles are (2x - 10)° and (x - 5)°

To find :

• The value of x

According to the question,

We know,

• Complementary angle = 90°

➞ (2x - 10)° + (x - 5)° = 90°

➞ 2x - 10° + x - 5° = 90°

➞ 3x - 15° = 90°

➞ 3x = 105°

➞ x = 105° ÷ 3

➞ x = 35°

• So, the value of x is 35°.

_____________________

★ Verification :

➞ (2x - 10)° + (x - 5)° = 90°

➞ 2x - 10° + x - 5° = 90°

➞ 3x - 15° = 90°

➞ 3(35°) - 15° = 90°

➞ 105° - 15° = 90°

➞ 90° = 90°

.°. L.H.S = R.H.S

Hence,verified.

Answer 2

Answer:

Given :-

• Angle (2x - 10) and (x - 5) are complementary angle

To Find :-

Angels

Solution :-

As we know that

• Complementary angle = 90⁰

$\tt \: 2x - 10 + x - 5 = 90$

$\tt \: 2x + x - 10 + 5 = 90$

$\tt \: 3x - 15 = 90$

$\tt \: 3x = 90 + 15$

$\tt \: 3x = 105$

$\tt \: x \: = \dfrac{105}{3}$

$\tt \: x = 35$

Hence :-

x is 35⁰

Angles are

$\sf \: 2x - 10 = 2(35) - 10 = 60$

$\sf \: x - 5 = 35 - 5 = 30$