Question

if the angles (2x-10)and (x-5)are complementary angles .find x​

Answer 1

$\large\red{\underline{\underline{\bf{\green{Given}}}}}$

Angles (2x - 10) and (x - 5) are complementary.

$\large\red{\underline{\underline{\bf{\green{To\:Find}}}}}$

Value of x

$\large\red{\underline{\underline{\bf{\green{Solution}}}}}$

We know that,

Complementary Angles are 90°

So,

$= > (2x - 10) + (x - 5) = 90 \\ \\ = > 2x - 10 + x - 5 = 90 \\ \\ = > 3x - 15 = 90 \\ \\ = > 3x = 90 + 15 \\ \\ = > x = \frac{105}{3} = 35$

Hence,

x = 35°

Angles are:-

=> (2x - 10) = 2× 35 - 10 = 70 - 10 = 60

=> ( x - 5) = 35 - 5 = 30

$\large\red{\underline{\underline{\bf{\green{Verification}}}}}$

Hence,

Complementary Angles are 90°

So,

=> 60° + 30° = 90°

=> 90° = 90°

=> L. H. S = R. H. S.

HENCE VERIFIED...

Answer 2

Answer:

sum of complementary angles = 90°

2x -10 + x -5 = 90

3x-15 = 90

3x = 90 +15

3x = 105

x = 105/3

x = 35