Question

If the angles (4x+4) and (6x-4) are complimentary angles, find x

Answer 1

$\huge\mathbb{SOLUTION}$

$\sf\underline{\red{Given:-}}$

2 angles which is complementary

Now we have to find the value of x

• We know that sum of complementary angles =90°

Now

$\sf\underline{\red{A.T.Q:-}}$

$\sf\implies (4x+4){}^{\circ}+(6x-4){}^{\circ}=90{}^{\circ}\\ \\ \sf\implies 10x{}^{\circ}=90{}^{\circ}\\ \\ \sf\implies x=\cancel{\dfrac{90}{10}}=9\\ \\ \sf\implies x=9{}^{\circ}$

$\sf \bullet 4\times 9+4=36+4=40{}^{\circ}\\ \\ \sf\bullet 6\times 9-4= 54-4 =50{}^{\circ}$

$\boxed{\sf{x=9{}^{\circ}}}$

$\boxed{\sf{angles= 50{}^{\circ}\:and\:40{}^{\circ}}}$

Answer 2

Answer:

Step-by-step explanation: Complimentary angles are those angles which have a sum of 90

Hence ( 4x + 4 ) +( 6x - 4 ) = 90

4x + 6x  + 4 - 4 = 90

x = 90 divide by 10

x = 9

first angle = 4 x 9 + 4 = 40

second angle = 6 x 9 - 4 = 50

Hence both the angles are 40 and 50