Question

If the angles 7A,11A are acute and cos11A=sin7A then find the value of A

Answer 1

Answer:

cos 11A = sin 7A

cos 11A = cos(90 - 7A)

Divide by cos on both sides

11A = 90 - 7A

11A + 7A = 90

18A = 90

A = 90/18

A = 5°

That's all I hope it will help you !!!!!