If the angles A, B and C of ABC be in AP and B:C = 4:3, find
angle A
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0
Answer:
c
Step-by-step explanation:
ANSWER
Let the angles be a,a+d,a+2d.
Then, a+a+d+a+2d=180
=a+d=60. So angle B=60
o
Now,
c b = sinC sinB
= 2 3
⟹sinC= 23 × 2 3
= 2 1
⟹C=45
o
So, ∠A=75
o
......AsA+B+C=180
Hence, option C is correct.
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Answer:
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