if the angles A,B,C of a triangle are in AP such that sin(2A+B)=1/2,then sin(B+2C)=
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4
Answer:
-1/2
Step-by-step explanation:
As A, B and C are in a triangle, we have A + B + C = π.
So...
sin ( B + 2C )
= sin ( 2(A + B + C) - (2A + B) )
= sin ( 2π - (2A + B) )
= sin ( -(2A + B) )
= - sin (2A + B)
= -1/2
N.B. The detail about A, B, C being in AP is unnecessary!
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2
Answer:
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