Math, asked by monibiju9353, 10 months ago

If the angles of a quadrilateral are 4x,x+10,2x-30 and 3x+20 find n

Answers

Answered by sumansharmaa972
1

Answer:

Step-by-step explanation:

4x+x+10+2x-30+3x+20=360

10x+0=360

10x=360

x=360/10

=36

n=36

Answered by sk940178
2

Answer:

36°

Step-by-step explanation:

We know that the sum of the four angles of a quadrilateral always equals 360°.

Now, given that the first angle is 4x, the second angle is x+10, the third angle is 2x-30 and finally, the fourth angle is 3x+20.

Hence, 4x+(x+10)+(2x-30)+(3x+20)=360

⇒10x =360

⇒ x= 36°.

Hence, x is =36°. (Answer)

The four angles are respectively, (36°×4)=144°

                                                        (36°+10°)=46°

                                                         (2×36°-30°)=42° and  

                                                          (3×36°+20°)=128°

Similar questions