If the angles of a quadrilateral are 4x,x+10,2x-30 and 3x+20 find n
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Answered by
1
Answer:
Step-by-step explanation:
4x+x+10+2x-30+3x+20=360
10x+0=360
10x=360
x=360/10
=36
n=36
Answered by
2
Answer:
36°
Step-by-step explanation:
We know that the sum of the four angles of a quadrilateral always equals 360°.
Now, given that the first angle is 4x, the second angle is x+10, the third angle is 2x-30 and finally, the fourth angle is 3x+20.
Hence, 4x+(x+10)+(2x-30)+(3x+20)=360
⇒10x =360
⇒ x= 36°.
Hence, x is =36°. (Answer)
The four angles are respectively, (36°×4)=144°
(36°+10°)=46°
(2×36°-30°)=42° and
(3×36°+20°)=128°
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