Question

if the angles of a quadrilateral are 4x° , [5(x+2)°] , (7x-20)° and [6(x+3)]° then find "x" ?​

Answer 1

Answer :

_______________________

Angles are as follows ;

• 1st angle = 4x°
• 2nd angle = (5x + 10)°
• 3rd angle = (7x - 20)°
• 4th angle = (6x + 18)°

We know that ;

Sum of angles of quadrilateral = 360°

⇒ 4x + 5x + 10 + 7x - 20 + 6x + 18 = 360

⇒ 22x + 8 = 360

⇒ 22x = 360 - 8

⇒ 22x = 352

⇒ x = 352/22

⇒ x = 16

Hence, the value of x is 16.

Answer 2

$\huge{\bold{SOLUTION:-}}$

NOTE :-

"Sum of angles in a quadrilateral is 360°"

So , 4x + 5(x+2) + (7x-20) + 6(x+3) = 360°

4x+5x+10°+7x-20°+6x+18=360°

22x+28-20=360°

22x+8=360°

22x=360°-8°

22x=352°

x=16°

ANGLES ARE AS FOLLOWS :-

4X = 4×16 = 64°

5X+10= 5×16+10 = 90°

7X-20=92°

6X+18= 114°