Question

if the angles of a quadrilateral are in A.P. whose
common difference is 10º, then the angles of the
quadrilateral are

Answer 1

Step-by-step explanation:

Sum of angles of a quadrilateral = 360° Common difference = 10 = d (say) If the first number be a, then the next four numbers will be a, a + 10, a + 20, a + 30 As per definition: a + a + 10 + a + 20 + a + 30 = 360° 4a + 60 = 360 4a = 300 or a = 75° Other angles: a + 10 = 75 + 10 = 85 a + 20 = 75 + 20 = 95 a + 30 = 75 + 30 = 105 Therefore, Angles are 75°, 85°, 95°, 105°Read more on Sarthaks.com - https://www.sarthaks.com/705483/the-angles-of-a-quadrilateral-are-in-ap-whose-common-difference-is-10-find-the-angles

Answer 2

Answer:

d=10

sum of all the angles of a quadrilateral= 360°

then the angles are

a+a+d+a+2d+a+3d= 360°

4a+ 6d= 360°

4a + 6 x 10 = 360°

4a=360°-60

4a=300

a=75

Step-by-step explanation:

so the angles are

a =75

a+d=75+10=85

a+2d=75+20=95

a+3d=75+30=105

hope this helps you

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