Math, asked by curiousbrain9403, 1 month ago

If the angles of a quadrilateral are in the ratio 2 : 3 : 6 : 7, then the difference of the largest and smallest angle is

Answers

Answered by BawliBalika
103

Given:

• angles of a quadrilateral are in the ratio 2:3:6:7

To Find:

difference of the largest and smallest angle

Solution:

Let the angles of the quadrilateral be :

2x, 3x, 6x and 7x

We Know That:

\boxed{\underline{\purple{\sf{sum\:of\: angles\:of\:a\:quadrilateral\:= 360°}}}}

\sf{\implies 2x + 3x + 6x + 7x = 360\degree}

\sf{\implies 18x = 360\degree}

\sf{\implies x = \frac{360}{18}}

\sf{\implies x = 20}

Now,

\sf{ the\:largest\:angle\:= 7x = 7 \times 20 = 140\degree}

\sf{ the\:smallest\:angle\:= 2x = 2 \times 20 = 40\degree}

therefore,

difference of the largest and smallest angle of the quadrilateral

\sf{\implies 140\degree - 40\degree}

\sf\red{\implies 100\degree}

Hence,

difference of the largest and the smallest angle is 100°

Answered by OyeeKanak
58

 \huge{ \boxed{ \pink{ \sf{Question:-}}}}

If the angles of a quadrilateral are in the ratio 2 : 3 : 6 : 7, then the difference of the largest and smallest angle is.

To find:-

  • The difference between the largest and the smallest angle.

Hint:-

  • To find the difference we will first find the measures of all angles.

We know that,

  • The sum of all angles of a quadrilateral is 360°.

Let the measure of angles be:-

  • 2x
  • 3x
  • 6x
  • 7x

 \huge{ \underline{ \boxed{ \bf{Solution :  -  }}}}

 \red{⇴} \mathfrak{2x + 3x + 6x + 7x = 360 \degree} \:

 \pink{⇴} \:  \bf18x = 360 \degree

 \green{⇴} \bf{x =  \frac{360}{180} }

 \blue{⇴} \sf{20 \degree}

Therefore the value of x is 20°

So the measures of angles:-

2x=2×20°=40°

3x=3×20°=60°

6x=6×20°=120°

7x=7×20°=140°

 \boxed{ \underline{ \mathfrak{ \green{Therefore  \: the  \: measure  \: of \:  the  \: largest \:  angle  \: is \:  140° \:  and  \: the \:  smallest  \: is \:  40°}}}}

Now we will find the difference between the largest and smallest angle.

  \large{ \red{⇝}}  \small\bf{140 \degree - 40 \degree}

 \large{ \pink{⇝}} \small 100 \degree

 \boxed{ \underline{ \red{ \mathfrak{Therefore \:  the \:  difference  \: between  \: the  \: largest \:  and  \: the  \: smallest  \: angles \:  is  \: 100°.}}}}

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