If the angles of a Quadrilateral are x degree,(2x+13) degree,(3x+10)degree ,(x-6)degree, find x
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To find the total sum of angles 180*(n-2) n = no of sides of closed polygon then for a quadrilateral 180*(4-2) 180*2=360 so x+(2x+13)+(3x+10)+(x-6)=360 x+2x+13+3x+10+x-6=360 6x+23-6=360 6x+17=360 (17 on another side) 6x=360-17 6x=343 x=343/6 x=114.34
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