Question

If the angles of a quadrilateral are x, x + 30°, x + 60 and 4x then the difference between greatest angle and the smallest is​

Answer 1

Answer:

115.8°

Step-by-step explanation:

STEP 1: Find the value of x

x + (x+30°) + (x+60°) + 4x = 360°

7x + 90° = 360°

7x = 360° - 90°

7x = 270°

x = 38.6°

STEP 2: Substitute the value of x

Angle 1: x = 38.6°

Angle 2: x+30° = 38.6° + 30° = 68.6°

Angle 3: x+60° = 38.6° + 60° = 98.6°

Angle 4: 4x = 4(38.6°) = 154.4°

STEP 3: Subtract the identified greatest and smallest angles

Greatest = 154.4°

Smallest = 38.6°

So, 154.4° - 38.6° = 115.8°