If the angles of a quadrilateral are x, x + 30°, x + 60 and 4x then the difference between greatest angle and the smallest is
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Answer:
115.8°
Step-by-step explanation:
STEP 1: Find the value of x
x + (x+30°) + (x+60°) + 4x = 360°
7x + 90° = 360°
7x = 360° - 90°
7x = 270°
x = 38.6°
STEP 2: Substitute the value of x
Angle 1: x = 38.6°
Angle 2: x+30° = 38.6° + 30° = 68.6°
Angle 3: x+60° = 38.6° + 60° = 98.6°
Angle 4: 4x = 4(38.6°) = 154.4°
STEP 3: Subtract the identified greatest and smallest angles
Greatest = 154.4°
Smallest = 38.6°
So, 154.4° - 38.6° = 115.8°
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