Question

if the angles of a quadrilateral are x°,(2x+13)°,(3x+10)°,(x-6)°find x

Answer 1

sum of angles is 360
=> x + 2x + 13 + 3x +10 + x- 6 = 360
=> 7x = 360-17 = 343
=> x = 49

Answer 2

Answer:

The value of x is 49°

Step-by-step explanation:

• In the question, The angles of a quadrilateral are x°, (2x+13)°, (3x+10)°, (x-6)°.
• Quadrilateral is a polygon which has four sides and four angles.
• The sum of the four angles of a Quadrilateral is 360°.
• So according to question,

x° + (2x+13)° + (3x+10)° + (x-6)°= 360°

• x+2x+13°+3x+10°+x-6°=360°
• x+2x+3x+x+13°+10°-6°=360°
• (keeping all x one side and numbers one side)
• 7x+17°=360°
• 7x=360°-17°
• (taking 17° to the other side of the equation)
• 7x= 343°
• x= 343°/7
• x=49°

The four angles of a the Quadrilateral are

x°= 49°

(2x+13)°= 2×49°+13°= 98°+13°= 111°

(3x+10)°= 3×49°+10°= 147°+10°= 157°

(x-6)°= 49°-6°= 43°

Conclusion:

The value of x is 49° and the four angles of the Quadrilateral is 49°,111°,157°and 43°.