if the angles of a quadrilateral are x°,(2x +13)°,(3x +10)°,(x-6)°,find x.
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Answered by
5
x+(2x+13)+(3x+10)+x-6) =360 (in degrees.)[Angle sum property of a quadrilateral]
→7x+17=360
→7x=343
→x=343/7
→x=49°
Forgive me if this is wrong. But this is what i get in this Circumstance....
→7x+17=360
→7x=343
→x=343/7
→x=49°
Forgive me if this is wrong. But this is what i get in this Circumstance....
geniushivm:
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Answered by
6
Hey dear here is your answer!!!
⏭️We can solve this by using angle sum property of quadrilateral ;
⏭️⭐We know that sum of all sides of a quadrilateral is 360°
⏭️⏪x+2x+13+3x+10+x-6 = 360°
⏪⏭️7x + 17=360°
⏭️⏪7x = 343
⏪⏭️x = 49
⭐⭐ Hope it helps u dear.....⭐⭐⭐
⏭️We can solve this by using angle sum property of quadrilateral ;
⏭️⭐We know that sum of all sides of a quadrilateral is 360°
⏭️⏪x+2x+13+3x+10+x-6 = 360°
⏪⏭️7x + 17=360°
⏭️⏪7x = 343
⏪⏭️x = 49
⭐⭐ Hope it helps u dear.....⭐⭐⭐
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