If the angles of a quadrilateral are x°, (x – 20)°, (x – 30)° and (x + 10)° find x.
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Sum of angles of quadrilateral is 360 degree.
x°+ (x – 20)°+(x – 30)° + (x + 10)°= 360°
x°+x – 20°+x – 30° + x + 10°= 360°
x°+x°+x°+x°– 20°– 30°+ 10°= 360°
4x°-40=360°
4x°= 360°+40°=400°
x=400/4°=100°
The angles = x°=100°, (x – 20)°=100-20°=80°,
x – 30°=100-30=70°, x + 10°= 100+10°=110° answer.
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