Math, asked by unknownmathnoob5, 19 days ago

if the angles of a quadrilateral are x° , x-20 , x-30 and x + 10 , find all the angles of the quadrilateral .

Answers

Answered by jnsnps
0

x + x- 20 + x - 30 + x + 10 = 360

x + x + x + x - 20 - 30 + 10 = 360

4x - 40 = 360

4x = 360 - 40 = 320

4x = 320

x = 320/4

x = 80

x = 80

x + 10 = 90

x - 20 = 60

x - 30 = 50

Answered by anjanbisoyi758
0

Answer:

x+x-20+x-30+x+10=360(Angle sum property of a quadrilateral is 360°)

•4x-40=360°

•4x=360+40

•4x=400

•x=400\4

•x=100

So, the first angle is x=100°

the second angle=x-20=100-20=80°

the third angle=x-30=100-30=70°

the fourth angle =x+10=100+10=110°

I hope you could understand this answer.

Thank you.

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