If the angles of a quadrilateral are x°,x-20°,x-30°,x+10°, then find x
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Answered by
0
Sum of all angles of an quadrilateral = 360°
=> x + x - 20 + x - 30 + x + 10 = 360
=> 4x - 40 = 360
=> x - 10 = 90
=> x = 100°
Angles are :-
x = 100°
x - 20 = 80°
x - 30 = 70°
x + 10 = 110°
=> x + x - 20 + x - 30 + x + 10 = 360
=> 4x - 40 = 360
=> x - 10 = 90
=> x = 100°
Angles are :-
x = 100°
x - 20 = 80°
x - 30 = 70°
x + 10 = 110°
Answered by
1
Hey Mate !!
Angles of Quadrilateral are : x°,x-20°,x-30°,x+10°
Sum of all angles in Quadrilateral = 360
ATP,
x° + x-20° + x-30° + x+10° = 360
4x - 40 = 360
4x = 360 + 40
4x = 400
x = 400/4
x = 100
Angles are :
x = 100
x - 20 = 100 - 20 = 80
x - 30 = 100 - 30 = 70
x + 10 = 100 + 10 = 110
HOPE THIS HELPS U...
Angles of Quadrilateral are : x°,x-20°,x-30°,x+10°
Sum of all angles in Quadrilateral = 360
ATP,
x° + x-20° + x-30° + x+10° = 360
4x - 40 = 360
4x = 360 + 40
4x = 400
x = 400/4
x = 100
Angles are :
x = 100
x - 20 = 100 - 20 = 80
x - 30 = 100 - 30 = 70
x + 10 = 100 + 10 = 110
HOPE THIS HELPS U...
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