Question

If the angles of a traingle are
in the ratio 1:
2:3, then the
smallest angle in radian is
π/3​

Answer 1

Answer:

$let \: the \: angles \: be \: x \: 2x \: and \: 3x \\ sum \: of \: angle \: of \: triangle = 180 ^{0} \\ = > x + 2x + 3x = 180 \\ = > 6x = 180 \\ = > x = \frac{180}{6} = 30 \\ angles \: are \: \: \: (in \: degree) \\ x = 30 \\ 2x = 60 \\ 3x = 90 \\ or \: \: \: (in \: radian)\\ x = \frac{30}{180} \pi = \frac{\pi}{6} \\ 2x = \frac{2\pi}{6} = \frac{\pi}{3} \\ 3x = \frac{3\pi}{6} = \frac{\pi}{2}$