If the angles of a triangle are in A.P., then the measure of one of the angles in radians is
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NOTE :- GIVEN QUESTION IS INCORRECT.
CORRECT QUESTION :-
The measure of angles of triangle are in A.P. The smallest angle is 40. Find the angles of the triangle in degree and in radian.
- Smallest angle = 40°
- let 2 other angle be = 40+d and 40 + 2d
NOW,
→ 40+ 40+d + 40 + 2d = 180
→ 120 + 3d = 180
→ 3d = 180 - 120
→ 3d = 60
→ d = 60/2
→ d = 20°
THEREFORE,
- Smallest angle = 40°
- other angle = 40+d = 40+20 = 60°
- larger angle = 40 + 2d = 40+2×20 = 80°
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