If the angles of a triangle are in A.P., then the measure of one of the angles in radians is
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Let the angles be (a-d)....a....(a+d)...
Sum of all angles is 180°...
a-d+a+a+d= 180°
3a=180°
a= 60°....
60° in radian = 60×(¶/180)
= ¶/3....
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