Question

. If the angles of a triangle are in ratio 2: 1: 3, then find measure of smallest angle.​

Answer 1

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$= 2 \ratio1 \ratio3$

Let the angles be x

$\therefore2x \ratio1x \ratio3x$

Total of all angels of a triangle is 180°

$\angle \: a + \angle \: b + \angle \: c = 18 {0}^{0}$

$2x + x + 3x = 180 {}^{0}$

$6x = 180 {}^{0}$

$x = \frac{180 {}^{0} }{6}$

$x = 30 {}^{0}$

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$\therefore2x = 2(30 {}^{0} ) = 60 {}^{0}$

$\therefore \: 1x = 1(30 {}^{0} ) = 30 {}^{0}$

$\therefore3x = 3(30 {}^{0} ) = 90 ^ {0}$

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$\therefore \: smallest \: angle = 30 {}^{0}$