If the angles of a triangle are in the ratio 2:3:4,then find the difference between the greatest and smallest angles.
Answers
Answered by
8
let the common ratio be X .
then, first side=2x ,second side=3x , third side =4x
2x+3x+4x=180
9x=180
X=20
smallest side =2x=2*20=40
greatest side=4x=4*20=80
difference=80-40=40 ans
then, first side=2x ,second side=3x , third side =4x
2x+3x+4x=180
9x=180
X=20
smallest side =2x=2*20=40
greatest side=4x=4*20=80
difference=80-40=40 ans
Answered by
14
Let the angles of triangle be 2x,3x,4x
sum of three angles of Δ is 180°
∴2x+3x+4X=180°
9x=180°
x=20°
∵2x=40° , 3x=60° , 4x=80°
now greatest angles is 80° nd smallest angle is 40°
difference =80-40=40
hope this will help
plzz marks it as brailist
Similar questions