Math, asked by yugsalecha41, 7 months ago

If the angles of a triangle are in the ratio 4:4:2, find the value of each angles​

Answers

Answered by 24323pragyasharma
5

Step-by-step explanation:

Let the angles of a triangle be 4x, 4x nd 2x.

Using angle sum property of a ∆,

4x + 4x + 2x = 180°

10x = 180°

x = 180/10

x = 18

1st angle = 4x

= 4×18

= 72°

2nd angle = 72°

3rd angle = 2x

= 2×18

= 36°

Answered by pmadhura136
1

Step-by-step explanation:

4:4:2 as we all know that sum of all angles of triangles is 180

let x be common

so, 4x +4x +2x = 180

10x= 180

x = 180/ 10

x=18

now put value of x in above

4x = 4 × 18= 72

4x = 4 ×18=72

2x = 2× 18= 36

hence angles are 72°+ 72° + 36°

Hope it will help you

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