if the angles of a triangle are in the ratio of 5 : 6 :9 then what is the difference between the greatest and smallest angle
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Answered by
14
let the angles be 5x,6x,9x
greatest angle = 9x
smallest angle = 5x
difference = 9x-5x = 4x
now,
5x +6x+9x=180°
20x = 180°
4x = 180/5°=36 °
difference is 36°
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greatest angle = 9x
smallest angle = 5x
difference = 9x-5x = 4x
now,
5x +6x+9x=180°
20x = 180°
4x = 180/5°=36 °
difference is 36°
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rithilekha:
thanks a lot
Answered by
18
let the 1st angle be 5x
let the 2nd angle be 6x
let the 3rd angle be 9x
5x + 6x + 9x = 180° (angle sum property of triangle)
20x = 180°
x = 180/20
x = 9
1st angle = 5x = 5 × 9 = 45°
2nd angle = 6x = 6 × 9 = 54°
3rd angle = 9x = 9 × 9 = 81°
to find the difference
largest angle - smallest angle
81° - 45°
= 36°
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let the 2nd angle be 6x
let the 3rd angle be 9x
5x + 6x + 9x = 180° (angle sum property of triangle)
20x = 180°
x = 180/20
x = 9
1st angle = 5x = 5 × 9 = 45°
2nd angle = 6x = 6 × 9 = 54°
3rd angle = 9x = 9 × 9 = 81°
to find the difference
largest angle - smallest angle
81° - 45°
= 36°
HOPE IT WILL HELP U FRIEND
✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️
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