Math, asked by sijanshre, 2 days ago

If the angles of a triangle are in the ration of 3:4:5, Find them.
who give me fast amswer I will give lowe​

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Answered by Anonymous
0

Answer:

45 60 75

Step-by-step explanation:

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Answered by AllenGPhilip
23

Answer:

Step-by-step explanation:

1.(a) Divide 4,800 in the ratio 2 : 3

Solution : Sum of the ratios is 2 + 3 = 5

First part = 4,800 × ²/₅ = 1,920

Second part = 4,800 × ³/₅ = 2,880

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1.(b) Angles of a triangle are in the ratio 3 : 4 : 5

∠A + ∠B + ∠C = 180°

Let the ratio be 3x : 4x : 5x

3x + 4x + 5x = 180

12x = 180

x = 15

So the angles are (3 × 15)° , (4 × 15)° , (5 × 15)°

45° , 60° , 75°

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1.(c) Given , the angles of a quadrilateral ABCD are in the ratio 1 : 2 : 3 : 4

Let ∠A = 1x  ∠B = 2x  ∠C = 3x  ∠D = 4x

In a quadrilateral ∠A+∠B+∠C+∠D = 360°

⇒ 1x + 2x + 3x + 4x = 360

⇒ 10x = 360

⇒ x = 360 ÷ 10 = 36

So the angles are,

∠A = (1 × 36)° = 36°

∠B = (2 × 36)° = 72°

∠C = (3 × 36)° = 108°

∠D = (4 × 36)° = 144°

Hence the angles are 36° , 72° , 108° , 144°

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10.(a) Given the perimeter of a rectangle is 124

The length of the rectangle is 18 more than the breadth

Let the length be 'x' and breadth be 'x + 18'

⇒ 2(l + b) = 124

⇒ 2(x + 18 + x) = 124

⇒ 2(2x + 18) = 124

⇒ 4x + 36 = 124

⇒ 4x = 88

⇒ x = 22

hence the breadth = (x) = 22

Length = (x + 18) = 22 + 18 = 40

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