If the angles of a triangle are x+40,x-20,x/2-10, then find only the value of x
Answers
Answered by
1
since the addition of three angles of a triangle is 180 degree
so here x+40+x-20+x/2-10=180
or 2x+x/2+10=180
or 5x/2=170
or 5x= 340
or x =68
so here x+40+x-20+x/2-10=180
or 2x+x/2+10=180
or 5x/2=170
or 5x= 340
or x =68
Answered by
0
hence x+40, x-20,x/2-10 are angles of triangle
x+40+x-20+x/2-10=180
or,2x+x/2=180-40+20+10
or,5x/2=170
or,5x=340
or,x=68
x+40+x-20+x/2-10=180
or,2x+x/2=180-40+20+10
or,5x/2=170
or,5x=340
or,x=68
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