Question

If the angles of elevation of a tower from two points distant a and b (a > b) from its foot and in the

same straight line from it are 300 and 600 , then the height of the tower is
​

Answer 1

Step-by-step explanation:

Let AB be the height of the tower and B be its foot

AB=h

BD=b

BC=a

∠ADC=60

∠ACB=30

in△ABC

tan30= h/a

h=a/√3-----1

tan60=h/b

h=b√3------2

multiply 1 and 2

h^2=a/√3×b√3

h^2=ab

h=√ab