If the angles of one triangle are respectively equal to the angles of another triangle then prove that the ratio of the corresponding sides is in the same ratio of the corresponding:- i) medians ii) bisector of the angles iii) altitudes
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Answer:
In △ABC AB=AC
⇒∠B=∠C (Angles opposite to equal sides are equal)
Now using angle sum property
∠A+∠B+∠C=180
∘
⇒80
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+∠C+∠C=180
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⇒2∠C=180
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−80
∘
⇒∠C=
2
100
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=50
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now ∠C+∠x=180
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(Angles made on straight line (AC) are supplementary)
⇒50
∘
+∠x=180
∘
⇒∠x=180
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−50
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=130
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