Math, asked by jagdev01455, 4 months ago

If the angles of quadrilateral are & x, (2x+13) (3x+10),
(x-6) & then find
the value of x

Answers

Answered by khashrul
1

Answer:

x = 49

Step-by-step explanation:

Sum of the angles of any quadrilateral is 360°

According to the problem:

x + (2x + 13) + (3x + 10) + (x - 6) = 360

=> 7x = 360 - 13 - 10 + 6 = 343

∴ x = 49


jagdev01455: thanks
jagdev01455: oh
Answered by ayushgade
2

Answer:

Given : angles - x , (2x+13) , (3x+10) ,(x-6)

All Angles of Quadrilateral are 360°

x + ( 2x+13 ) + ( 3x+10 ) + ( x-6) = 360

7x + 13 + 10 -6 = 360

7x + 17 = 360

7x = 360 - 17

7x = 343

x = 343/7

x = 49

x = 49°

That Is the Value Of X is 49°

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