Question

if the angles of quadrilateral are x, (x+20), 2x and (3x-80) then find the greatest angle

1st answer will get brainliest

Answer 1

We Know that ,

Sum of all 4 angles in a Quadrilateral = 360° .

then,

$\tt \: x + x + 20 + 2x + 3x - 80 = 360$

$\tt \: 7x - 60 = 360$

$\tt \: 7x = 420$

$\tt \boxed{ \boxed{ \tt \: x = 60 \degree}}$

The Greatest Angle is 2x

2(60) = 120°

Mark as Brainliest answer please my friend

Answer 2

Sum of all interior angles of quadrilateral is 360°.

=> x + x + 20 + 2x + 3x - 80 = 360

=> 7x + 20 - 80 = 360

=> 7x - 60 = 360

=> 7x = 360 + 60

=> 7x = 420

=> x = 420/7

=> x = 60

Angles =>

x = 60°

x+20 = 60 + 20 = 80°

2x = 2 × 60 = 120°

3x - 80 = 3×60 - 80 = 180 - 80 = 100°

2x is greatest angle having measure 120°.