Question

if the angles of Septagon are in the ratio 2 : 4 : 3 : 1 : 1 : 2, then calculate the measure of these angle​

Answer 1

Answer:

54°

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Answer 2

""" ❤️ Answer ❤️ """

Let the angles of the Pentagon be 2x,3x,4x,5x,and6x

Let n be the number of sides.

In a regular Pentagon, sum of interior angles

=

(n−2)×

180 ∘

= (5−2)×

180 ∘

540 ∘

According to the question,

2x+ 3x+ 4x+ 5x+ 6x=

540 ∘

⇒ 20x=

540 ∘

⇒ x=

20

540 ∘

=

27 ∘

The interior angles of the given pentagon

2x= 2×

27 ∘

54 ∘

3x= 3×

27 ∘

81 ∘

4x= 4×

27 ∘

108 ∘

5x= 5×

27 ∘

135 ∘

6x= 6×

27 ∘

162 ∘

thus, the interior angles of the Pentagon are

81

∘

108

∘

135

∘

54 ∘

and

162 ∘

Sum of first and second angle

=

54 ∘

81 ∘

135