If the angles of the traingle are in ratio 3:2:4 find the measure of largest angle
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The ratio is 3:2:4
let the angles be 3x, 2x and 4x
3x+4x+2x=180(°angle sum property of a triangle)
9x=180°
X=20°
3x =3×20
= 60°
2x=2×20
=40°
4x=4×20
=80°
Therefore the largest angle is 80°
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let the angles be 3x, 2x and 4x
3x+4x+2x=180(°angle sum property of a triangle)
9x=180°
X=20°
3x =3×20
= 60°
2x=2×20
=40°
4x=4×20
=80°
Therefore the largest angle is 80°
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Let the angles be 3x 2x & 4x
so as we know 3x +2x+4x= 180 (angle sum property )
19x= 180
x= 180/9
x= 20
so the angles are
3x20=60
2x20= 40
4×20= 80
so the largest angle is 80
so as we know 3x +2x+4x= 180 (angle sum property )
19x= 180
x= 180/9
x= 20
so the angles are
3x20=60
2x20= 40
4×20= 80
so the largest angle is 80
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