Question

if the angles of triangle are (2x +30)°, (5x-10) ° and 3x+40) °.then the angles of the triangle are​

Answer 1

Answer:

Sum of all interior triangle angle is 180°

then ,

2x+30+5x-10+3x+40=180°

10x+60=180°

10x=180°-60°

x=120/10

x=120°

Answer 2

Answer: 54°,50° and 76°

Step-by-step explanation:

Using angle some property of a triangle,

(2x+30)°+(5x-10)°+(3x+40)°=180°

10x+60° = 180°

10x = 180°-60°

x = 120/10 = 12°

Hence, angles of the triangle are:

(2x+30)° = 2×12+30= 54°

(5x-10)° = 5×12-10= 50°

(3x+40)° = 3×12+40= 76°