Question

if the angles of triangle are (x - 40 ) , ( x - 20 ) & ( half of x - 10 ) . find the value of x ​

Answer 1

(x-40)+(x-20)+(1/2x-10)=180°

x-40+x-20+1/2x-10=180°

5x/2-70=180

5x=360°-70°

5x=290°

x=290/5=58°

Answer 2

x-40+x-20+(x-10)÷2 =180

2x-60+(x-10)÷2=180

[4x-120+x-10]÷2=180

5x-130=360

5x=360+130

5x=490

x=490÷5

x=98