if the angles subtended by the chords of a circle at the centre are equal then the chords are equal
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Given: ∠AOB and ∠POQ are two equal angles subtended by chords AB and PQ of a circle at its centre O. To Prove : AB = PQ Proof : In ∆AOB and ∆POQ, OA = OP [Radii of a circle] OB = OQ [Radii of a circle] ∠AOB = ∠POQ [Given] ∴ ∆AOB ≅ ∆POQ [By SAS] ∴ AB = PQ [By cpctc]
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