Question

If the angles triangle are (3x)°‚(2x-7)°‚and (4x-11)°‚then find the value of x

Answer 1

3x+(2x-7)+(4x-11)=180
3x+2x-7+4x-11=180
9x-18=180
9x=198
x=198/9
=22

Answer 2

Hlo friend.. Cutiepie Here..

Here is ur answer :

Let Ist angle - 3x°

IInd angle - 2x - 7°

IIIrd angle - 4x-11°


Sum of all the internal angles of a triangle is 180.

Ist + IInd + IIIrd = 180

$3x + 2x - 7 + 4x - 11 = 180$


$9x = 180 + 18$


$9x = 198$


$x = \frac{198}{9}$


$x = 22$


Ist angle - 3 × 22 = 66°

IInd angle - 2(22)-7= 44 - 7 = 37°

IIIrd angle - 4(44) - 11 = 88-11 = 77°



HOPE IT HELPS YOU..

REGARDS
@sunita