Question

If the angular momentum of an electron is 3.16×10^-34 kgm^2/s and the radius and energy of an orbit in which the above electron is present is 0.6×10^-10m and 2.4 × 10^-18J , respectively then calculate the radius and energy of 2nd orbit of that atom.

Answer 1

Hii friend,

I hope my answer is correct.

Radius of the electron in the 2ñd orbit is

Rñ => n² ×0.53 A° [Bohr 's formula]

R 2 => 4×0.53 ×10^-10

R2 => 2.12 ×10^-10m.................(1)

Energy of the electron:-

Eñ =>-13.6/n² eV

E2 => -13.6/4

E2 =>-3.4 eV.

(The negative sign indicated that as energy increases, the orbit increases).

I hope this answer is correct. If it is wrong sorry for it.

Hope this helps you a little!!!

Answer 2

The correct answer is

Radius- 0.234 A

Energy- 1.076*10^-19 J

Hope it helps.