Physics, asked by keyurpatel5220, 6 months ago

If the angular velocity of a merry-go-round is 60 degree
sec and you are 3.5 m from the centre of rotation
your linear velocity will be :-
(1)
22
m/s
7.
(2)
7
- m/s
3
7 п
(3) m/s
6
(4) at m/s

Answers

Answered by krishnmadhavasawa
1

Answer:

answer is 3 ,7π/6 m/s

Explanation:

it is the most correct answer and I am damm sure .

Answered by mithun890
3

Answer:

Explanation:

  • w=60 degree/ sec\\,
  • 1 degree= \pi /180\\  
  • angular velocity is find by,

                     ∴w= 60 ×\pi \\/180

                       w=\pi /3  rad/sec

  • given ' r ' =  3.5m

         formula for linear velocity is given as ,

                 v =rw

  •  lets substitute all teh values,

                       v=\pi /3 ×  3.5

                          = 22/7 ×  1/3 ×  3.5   (∴ \pi =22/7 )

                          =11/2 m/s   or

              'multiply  both up and down with 2',

                          =22/6

           'now divide both up and down with 7'

                          =7\pi /6 - m/s.

∴ the linear velocity will be 7\pi / 6 or 11/3 .

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