Question

If the angular velocity of a merry-go-round is 60 degree
sec and you are 3.5 m from the centre of rotation
your linear velocity will be :-

Answer 1

I hope this helps!!!!!!

Answer 2

Given:

The angular velocity of a merry-go-round is 60 °/sec and located 3.5 m from the centre of rotation.

To find:

Linear velocity ?

Calculation:

• Angular velocity is the rotational analogue of linear velocity. It is an axial vector.

• 60°/sec = 60 × π/180 rad/sec = π/3 rad/sec.

Now, general expression relating the two quantities:

$\rm v = \omega \times r$

$\rm \implies \: v = \dfrac{\pi}{3} \times 3.5$

$\rm \implies \: v = \dfrac{1}{3} \times \dfrac{7}{2} \times \dfrac{22}{7}$

$\rm \implies \: v = 3.66 \: m {s}^{ - 1}$

So, linear velocity at that location is 3.66 m/s.