If the Annual stream flow from a 10 Km2 catchment is 107 m3 what would be the corresponding average depth of rainfall in cm?
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Thus, for example, if the annual stream flow from a 10 km2 catchment is 107 m3, it corresponds to a depth of æ 107 ö çè 10 ´ 106 ÷ø = 1 m = 100 cm.
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The corresponding average depth of the rainfall would be 0.107 cm.
Given:
Catchment bed area = 10 km²
Annual streamflow = 107 m³
To find: Average depth of the rainfall in cm
Solution: Let us assume,
Length of catchment bed = l
Breadth of catchment bed = b
Depth of rainfall = h
Now,
Annual streamflow = 107 m³
⇒ Volume of the catchment area = 107 m³
⇒ l × b × h = 107
But area of catchment bed = 10 km²
⇒ l × b = 100000 m²
⇒ 100000 × h = 107
⇒ h = 0.00107 m
⇒ h = 0.107 cm
The average depth of rainfall is 0.107 cm Answer
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