if the apply a push of 5n on the heavier mass the force on the lighter mass will be
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Answer:2N
Explanation:
1• F=ma
=(m1+m2)a
First we need to find the acceleration:
a=F/(m1+m2)
=5/4+6
=5/10
=0.5 m/s^2
Now the force on the lighter mass is:
2• F=m2×a
=4×0.5
=2N
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