Question

if the are A of the triangle with vertices at (2,a) (a,2) and (-2,-1) in 5, find the possible of A.

Answer 1

Answer:

Step-by-step explanation:

Let ABC be a triangle with vertices A(2,a), B(a,2) & C(-2,-1)

Area of triangle ABC = 5 sq. units (Given)

=>1 ÷ 2 | x1 (y2 - y3) + x2 (y3 - y1) + x3 (y1 - y2) | =5

=> | 2 [ 2-(-1) ] + a (-1 - 2) + (-2) (a - 2) | = 5×2

=> | 2(3) + a(-3) -2a + 2 | = 10

=> | 6 - 3a - 2a + 2 | = 10

=> 8 - 5a = 10

=> 5a = -2

=> a = -2/5