Question

if the are of two squares is 36 sq cm and 64 sq cm respectively. what will be the side of the square whose perimeter is equal to the sum of the perimeters of these two squares?​

Answer 1

Answer:

Length of the side of the square is 14 cm. whose perimeter is equal to the sum of the perimeters of that two squares.

Step-by-step explanation:

Area of 1st square = 36 sq.m.

As we know that;

Area of square= side  × side

∴ side = $\sqrt{area}$

          = $\sqrt{36}$ = 6cm.

Perimeter of square = 4 × side

                                   = 4 × 6 = 24 cm.

Area of 2nd square = 64 sq.cm.

Side = $\sqrt{area}$

        = $\sqrt{64}$ = 8 cm.

Perimeter of 2nd square= 4 × side

                                        = 4 × 8 = 32 cm.

Perimeter of required square = perimeter of 1st square + perimeter of 2nd square

                                               =  24 + 32 =56 cm.

Side of the required square = perimeter / 4

                                               = 56 / 4

                                               = 14 cm.

Answer 2

Answer:

if the are of two squares is 36 sq cm and 64 sq cm respectively. what will be the side of the square whose perimeter is equal to the sum of the perimeters of these two squares?