Question

If the area covered
by both orange and
yellow blocks is 2 m2
what will be the
minimum area (in m2
) covered by the
grey blocks?
Square
Side -'a'
Square
Side - 'c
Square
Side - 'b'
Square
Side - 'd​

Answer 1

Answer:

We know, that square is a rectangle whose length and breadth are equal. In a square all four sides are equal. Therefore, area of a square = (side × side) square units = (side)2 square units.

Answer 2

The complete question is as follows:

If the area covered by both orange and yellow blocks is 2 $m^2$, what will be the minimum area (in $m^2$ ) covered by the grey blocks?

a . 16

b. 12

c. 4

d. 8

Answer:

The minimum area covered by the grey blocks is 8$m^2$. Option d) 8 $m^2$ is correct.

Given:

The area covered by both orange and yellow blocks is 2 $m^2$.

To find:

The minimum area covered by the grey blocks.

Formula used:

• Area of a square = (side × side) square units = $(side)^2$ square units.
• Area of a rectangle = Length × breadth square units.

Step-by-step explanation:

Since, the area covered by both orange and yellow blocks is 2 $m^2$.

The length will be 2 m and the breadth will be 1 m.

So, the length of grey blocks will be 2+2 = 4m

The width of grey blocks will be 1+1 = 2m

Therefore, the area covered by grey blocks is

= 4 × 2

= 8 $m^2$

Thus, the minimum area covered by the grey blocks is 8$m^2$. Option d) 8 $m^2$ is correct.