if the area formed by line 2x+3y-k=o is 12 sq units then find k
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2x+ 3y = k
Devide by k
2/k*x +3/k *y = 1
Area of triangle = 1/2 *k/3 *k/2
12 = k^2/12
K^2= 144
K = 12
Devide by k
2/k*x +3/k *y = 1
Area of triangle = 1/2 *k/3 *k/2
12 = k^2/12
K^2= 144
K = 12
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