If the area inclosed between the curves y²=4ax and x²=4ay is 16/3 sq units then find the value of a
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Hey mate
your answer is here
so,
given that area = 16/3
so,
a = 1 or a = -1
your answer is here
so,
given that area = 16/3
so,
a = 1 or a = -1
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