Question

If the area is halved then resistance become , considering volume is constant

Answer 1

Answer:

resistance in this case becomes 4 times

Explanation:

let original length of the wire be l and original area be a.

original resistance(r)=Pl/a

then volume=al

now area(A) becomes 1/2a

let new length be L

so keeping volume constant we get

LA=al

or, L×1/2a=l×a

or, L=2l

new resistance(R) =PL/A

=P×2l/1/2a

= P4l/a

=4Pl/a

now r/R. =. ( Pl/a)/(4Pl/a)

or, r/R=1/4

or, R=4r

I hope it helps you

Mark me as brainliest.