Question

If the area of a circle decreases by 36%, then the radius of a circle decreases by

Answer 1

Let initial radius of the circle is r then, area of circle is πr²
Now, area of circle is decreased by 36% .
e.g., area of new circle = πr² - 36% of πr² = 0.64 πr²
area of new circle = π(0.8r)²
Hence, raidus of new circle = 0.8r
% decreased in radius = change in radius/intial radius × 100
= (r - 0.8r)/r × 100
= 0.2r/r × 100
= 20 %

Hence, radius of circle is decreased by 20%

Answer 2

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